5p^2=4+p

Solution for 5p^2=4+p equation:

5p^2=4+p

We move all terms to the left:

5p^2-(4+p)=0

We add all the numbers together, and all the variables

5p^2-(p+4)=0

We get rid of parentheses

5p^2-p-4=0

We add all the numbers together, and all the variables

5p^2-1p-4=0

a = 5; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·5·(-4)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-9}{2*5}=\frac{-8}{10}
=-4/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+9}{2*5}=\frac{10}{10}
=1
$